// Copyright (c) 2009 The Go Authors. All rights reserved. // // Redistribution and use in source and binary forms, with or without // modification, are permitted provided that the following conditions are // met: // // * Redistributions of source code must retain the above copyright // notice, this list of conditions and the following disclaimer. // * Redistributions in binary form must reproduce the above // copyright notice, this list of conditions and the following disclaimer // in the documentation and/or other materials provided with the // distribution. // * Neither the name of Google Inc. nor the names of its // contributors may be used to endorse or promote products derived from // this software without specific prior written permission. // // THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS // "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT // LIMITED TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR // A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT // OWNER OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, // SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT // LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, // DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY // THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT // (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE // OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE. package common import ( "crypto/rand" "crypto/rsa" "hash" "io" "math/big" "github.com/cloudflare/circl/blindsign/blindrsa/internal/keys" ) var ( bigZero = big.NewInt(0) bigOne = big.NewInt(1) ) // incCounter increments a four byte, big-endian counter. func incCounter(c *[4]byte) { if c[3]++; c[3] != 0 { return } if c[2]++; c[2] != 0 { return } if c[1]++; c[1] != 0 { return } c[0]++ } // mgf1XOR XORs the bytes in out with a mask generated using the MGF1 function // specified in PKCS #1 v2.1. func mgf1XOR(out []byte, hash hash.Hash, seed []byte) { var counter [4]byte var digest []byte done := 0 for done < len(out) { hash.Write(seed) hash.Write(counter[0:4]) digest = hash.Sum(digest[:0]) hash.Reset() for i := 0; i < len(digest) && done < len(out); i++ { out[done] ^= digest[i] done++ } incCounter(&counter) } } func encrypt(c *big.Int, N *big.Int, e *big.Int, m *big.Int) *big.Int { c.Exp(m, e, N) return c } // decrypt performs an RSA decryption, resulting in a plaintext integer. If a // random source is given, RSA blinding is used. func decrypt(random io.Reader, priv *keys.BigPrivateKey, c *big.Int) (m *big.Int, err error) { // TODO(agl): can we get away with reusing blinds? if c.Cmp(priv.Pk.N) > 0 { err = rsa.ErrDecryption return } if priv.Pk.N.Sign() == 0 { return nil, rsa.ErrDecryption } var ir *big.Int if random != nil { // Blinding enabled. Blinding involves multiplying c by r^e. // Then the decryption operation performs (m^e * r^e)^d mod n // which equals mr mod n. The factor of r can then be removed // by multiplying by the multiplicative inverse of r. var r *big.Int ir = new(big.Int) for { r, err = rand.Int(random, priv.Pk.N) if err != nil { return } if r.Cmp(bigZero) == 0 { r = bigOne } ok := ir.ModInverse(r, priv.Pk.N) if ok != nil { break } } rpowe := new(big.Int).Exp(r, priv.Pk.E, priv.Pk.N) // N != 0 cCopy := new(big.Int).Set(c) cCopy.Mul(cCopy, rpowe) cCopy.Mod(cCopy, priv.Pk.N) c = cCopy } m = new(big.Int).Exp(c, priv.D, priv.Pk.N) if ir != nil { // Unblind. m.Mul(m, ir) m.Mod(m, priv.Pk.N) } return m, nil }